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pashok25 [27]
3 years ago
11

If there is 1/2 of a pizza and jonas only wants 1/3 of the pizza, how much will he get?

Mathematics
2 answers:
slamgirl [31]3 years ago
8 0

Answer:

Option C is the right answer.

Step-by-step explanation:

1/2 × 1/3 = 1/6

Verizon [17]3 years ago
6 0

Answer:

C. 1/6

Step-by-step explanation:

it is not a whole pizza, it is half, so 1/3 of a half pizza is equal to 1/6 a whole pizza.

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A bicycle has a circumference of approximately 81.68 inches
Blizzard [7]

Answer:

25

Step-by-step explanation:

Don't ask

8 0
3 years ago
How many inches did the height of the plant increase between weeks 3 and 4
Allisa [31]
It increased a total of 4 inches.
6 0
3 years ago
Read 2 more answers
PLEASE HELP!! Will give Brainliest!
Greeley [361]

Answer:

A) 11/36

Step-by-step explanation:

x + 4/9 = 3/4

get a common denominator of 36  (4*9 = 36)

x + 4/9 * 4/4 = 3/4 * 9/9

x + 16/36 = 27/36

subtract 16/36 from each side

x + 16/36 - 16/36 = 27/36 -16/36  

x = (27-16)/36

x = 11/ 36


6 0
3 years ago
Read 2 more answers
A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo
SpyIntel [72]

Answer:

R_{in}=0.2\dfrac{mL}{min}

C(t)=\dfrac{A(t)}{30000}

R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}

A(t)=300+2700e^{-\dfrac{t}{1500}},$  A(0)=3000

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

R_{in}=(concentration of chlorine in inflow)(input rate of the water)

=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}

(c) Concentration of chlorine in the pool at time t

Volume of the pool =30,000 Liter

Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}

(d) Rate at which the chlorine is leaving the pool

R_{out}=(concentration of chlorine in outflow)(output rate of the water)

= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.2- \dfrac{A(t)}{1500}

We then solve the resulting differential equation by separation of variables.

\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}

Taking the integral of both sides

\int(Ae^{\frac{t}{1500}})'=\int 0.2e^{\frac{t}{1500}} dt\\Ae^{\frac{t}{1500}}=0.2*1500e^{\frac{t}{1500}}+C, $(C a constant of integration)\\Ae^{\frac{t}{1500}}=300e^{\frac{t}{1500}}+C\\$Divide all through by e^{\frac{t}{1500}}\\A(t)=300+Ce^{-\frac{t}{1500}}

Recall that when t=0, A(t)=3000 (our initial condition)

3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}

3 0
3 years ago
Simplify the expression 8^2 +9 (12/3x2)- 7
Zarrin [17]
1)12 ÷ 3 = 4. 
2) 4×2= 8.
3) 9× 8= 72.
4) 8² = 64
5) 64+ 72 = 136
6) 136 - 7 = 129.

If you just want to simplify the expression you get: 8² + 9(8) - 7
But when you simplify that you get the answer below. 
ANSWER: 129
6 0
4 years ago
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