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3 years ago

Find the component form for vector AB given the initial point A (1, 7, -9) and terminal point B (-2, 18, 4).

1 answer:

5 0

To find each of the components of AB we can find the different between the components on the terminal and initial points, doing that, we find:

AB = (-2 - 1, 18 -7, 4 - (-9)) = (-3, 11, 13).

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Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

3 years ago

Which of the following demonstrates the Distributive Property?

Sever21 [200]

2(3a+4) 6a+8=6a+8.....

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If |u| = 10, |v| = 8, and the angle formed between them is 60°, then u · v = ?

Gre4nikov [31]

U . v = |u| . |v| cos 60 = 10 * 8 * 0.5 = 40 This is called the scalar (or dot) product.

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3 years ago

Hiro painted his room at a rate of 8 square meters per hour. After 3 hours of painting, he had 28 square meters left to paint. L

coldgirl [10]

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3 years ago

Below are two parallel lines with a third line intersecting them.

Ulleksa [173]

Answer:

x = 88

Step-by-step explanation:

These angles are same side exterior angles, and when the lines are parallel, same side exterior angles are supplementary

x + 92 =180

Subtract 92 from each side

x+92-92=180-92

x =88

4 0

3 years ago

Read 2 more answers