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3 years ago

The perimeter of the garden The area of the garden

Mathematics

1 answer:

KatRina [158]3 years ago

8 0

Answer:

the square is 32 but idrk about the whole thing

Step-by-step explanation:

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Harold bought 3 points of red apples and 4.2 pounds of green apples from a grocery store, where both kinds of apple are 1.75 a p

andrew11 [14]

Answer:

12.6

Step-by-step explanation:

total weight of apples = 3+ 4.2

= 7.2 pounds

total money spent on apples = 1.75 × 7.2

= $12.6

5 0

3 years ago

Read 2 more answers

It took Michala 4 hours to sew 9 scarfs. How many scarfs could she make in 24 hours

aksik [14]

<h2>4 hours → 9 scarfs</h2><h2>8 hours → 18 scarfs</h2><h2>12 hours → 27 scarfs</h2><h2>16 hours → 36 scarfs</h2><h2>20 hours → 45 scarfs</h2><h2><u>24 hours → 54 scarfs</u></h2><h2><u /></h2><h3>Therefore, Michala can sew 54 scarfs in 1 day.</h3>

3 0

3 years ago

For which value of x is xyza a rectangle

lisabon 2012 [21]

Well each angle in a rectangle is 90°, so if x is an angle, it's 90°

I hope that helps!

7 0

3 years ago

A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the

Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average age = 25 years

$\sigma$ = population standard deviation = 1.8 years

n = sample of students = 36

$\mu$ = population average age

So, 98% confidence interval for the average age, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < ${\bar X - \mu}$ < $2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

P( $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ < $\mu$ < $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} }$ , $\bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} }$ ]

= [ $25 - 2.3263 \times {\frac{1.8}{\sqrt{36} }$ , $25 + 2.3263 \times {\frac{1.8}{\sqrt{36} }$ ]

= [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0

3 years ago

What is the least common multiple of 8 and 9?<br><br><br><br> Enter your answer in the box.

Contact [7]

Answer:

Step-by-step explanation:

The LCM is when you find the lowest factor that 2 or more numbers share.

For 8 and 9,you would just need to keep multiplying each other until you find the same numbers. It would look something like this.

8,16,24,32,40,48,56,64,72..... etc.

9,18,27,36,45,54,63,72,81..... etc.

You can see how they both have the same factor (72), and since that is the lowest factor (which means I can find a lower factor then 72) then your LCM of 8 and 9 should be 72 :)

4 0

3 years ago

The perimeter of the garden The area of the garden​

The perimeter of the garden The area of the garden