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Ad libitum [116K]
2 years ago
11

Reflect the point (a) in the x-axis and (b) in the y-axis (4,5)and (1 1/2, -1/4)

Mathematics
1 answer:
gulaghasi [49]2 years ago
6 0

(4,5)

a) -4,5

b) 4,-5

(11/2 , -1/4)

a)-11/2,-1/4

b)11/2,1/4

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According to the Substitution Property of Equality: If y = -5 and 7x + y = 11, then _______ . Question 9 options: 7(-5) + y = 11
ycow [4]

Answer:

7x - 5 = 11

Step-by-step explanation:

To solve for x, substitute y = -5 into the equation 7x + y = 11.

This becomes 7x + (-5) = 11 or 7x - 5 = 11.

7 0
3 years ago
PLEASE HELP ME!!! ON THE FIRST QUESTION!
MrMuchimi

Answer:

9ber

Step-by-step explanation:

Aight will do

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2 years ago
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Describe how you would estimate the square root of a number that is not a perfect square without using a calculator. lets say n
scZoUnD [109]
To get the square root of imperfect square we can use the formula , which is usually accurate to about two decimal places,
√X =√S +(X-S)2√S
Where, X = the number you want the square roof of, and S is the closest square you know to x.
For example 75 is an imperfect square
Thus, X=75 and thus the nearest number S = 81, this ,means √81 =9.
Putting this into the formula;
√75= 9+(75-81)/2/2(9)
      =  9 + -6/18 
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6 0
3 years ago
Will give brainliest !Select the correct answer.
QveST [7]

Answer:

im not sure but i think c.

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Step-by-step explanation:

4 0
3 years ago
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What are the solutions of 3(x – 4)(2x - 3) = 0? Check all that apply.
dangina [55]

Answer:

The solution to the equation is:

x=4,\:x=\frac{3}{2}

Step-by-step explanation:

Given the equation

3\left(x-4\right)\left(2x-3\right)=0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x-4=0\quad \mathrm{or}\quad \:2x-3=0

now solving

x - 4 = 0

adding 4 to both sides

x - 4 + 4 = 0 + 4

simplifying

x = 4

and also solving

2x - 3 = 0

adding 3 to both sides

2x - 3 + 3 = 0 + 3

simplifying

2x = 3

divide both sides by 2

\frac{2x}{2}=\frac{3}{2}

simplifying

x=\frac{3}{2}

Therefore, the solution to the equation is:

x=4,\:x=\frac{3}{2}

4 0
2 years ago
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