The number of months overcharged for 1 gallon of leaky water = 1 1/3
= 4/3
Let us assume the quantity of water overcharged = w
Let us assume the time in months = t
Then, the equation modelling this direct variation is
w = (3/4)t
When w = 5, then
5 = (3/4) * t
20 = 3t
t = 20/3
= 6 2/3
From the above deduction, we can conclude that the first option or option "A" is the correct option. I hope the answer helps you.
Two solutions were found :<span> t = 8 t = 0</span>
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "t2" was replaced by "t^2".
Step by step solution :Skip Ad
<span>Step 1 :</span><span>Step 2 :</span>Pulling out like terms :
<span> 2.1 </span> Pull out like factors :
<span> t2 - 8t</span> = t • (t - 8)
<span>Equation at the end of step 2 :</span> t • (t - 8) = 0
<span>Step 3 :</span>Theory - Roots of a product :
<span> 3.1 </span> A product of several terms equals zero.<span>
</span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span>
</span>We shall now solve each term = 0 separately<span>
</span>In other words, we are going to solve as many equations as there are terms in the product<span>
</span>Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
<span> 3.2 </span> Solve : t = 0<span>
</span> Solution is t = 0
Solving a Single Variable Equation :
<span> 3.3 </span> Solve : t-8 = 0<span>
</span>Add 8 to both sides of the equation :<span>
</span> t = 8
Two solutions were found :<span> t = 8<span> t = 0</span></span>
X=4 this is because 4 times (x+1)-5=11 the 1x then just turns to x because you can’t have a 1 next to x when it’s just one x.
4*(x+1)-5=11
4(x)-5=11
4x-5=11
+5=11
—————
4x=16
4. 4
———-
X=4
