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fomenos
2 years ago
6

-4.326 + (-0.32) ÷ 0.4

Mathematics
1 answer:
Schach [20]2 years ago
3 0

Answer:

-5.126

Step-by-step explanation:

PEMDAS

-4.326 + (-0.32) ÷ 0.4

<u>-0.32 ÷ 0.4</u>

= -0.8

<u>-4.326 + (-0.8)</u>

= -4.326 - 0.8

= -5.126

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3 years ago
Kelly bought 3 pounds of chicken for 6.99 per pound 20 pounds of dog food 1.95 Per pound prices include the sales tax Kelly gav
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6 0
3 years ago
The test scores of 32 students are listed below. Construct a boxplot for the data set and include the values of the 5-number sum
zhenek [66]

Answer:

Boxplot is constructed using quartiles and 5 No. summary means including minimum value of data, 1st quartile, 2nd quartile, 3rd quartile and maximum value of data.

As data already in increasing order, we find quartiles using the following formula,

value\:of\:K_{th}\:Quartile\:,\, Q_k=\:value\:of\:(\frac{k\times{(n+1)}}{4})\,\:th\,observation

where n = No. of Observations.

∴, 1st Quartile,

Q_1 = \frac{1\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=8.25\,th\:observation\\\: \:\:= 8th\,+0.25(9th-8th)\\\:\:\:= 55 + 0.25(57-55)\\\:\:\:= 55.5

2nd Quartile,

Q_2 = \frac{2\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=16.5\,th\:observation\\\: \:\:= 16th\,+0.5(17th-16th)\\\:\:\:= 69 + 0.5(70-69)\\\:\:\:= 69.5

3rd Quartile,

Q_3 = \frac{3\times{(32+1)}}{4}\, th\:\:observation\\\\ \:\:\:=24.75\,th\:observation\\\: \:\:= 24th\,+0.75(25th-24th)\\\:\:\:= 79 + 0.75(81-79)\\\:\:\:= 80.5

Minimum value of data = 32 & Maximum value of data = 99

So, Values of 5 no. that are to ne include in Boxplot are 32, 55.5, 69.5, 80.5, 99.

BoxPlot is attached with this ans.

7 0
3 years ago
I only need the first one ( 45% of 30) but please keep in mind that I do need help with the other two, but they are optional.
Usimov [2.4K]
45% of 30 is 13.5
40% of 175 is 70
20% of 60 is 12
6 0
3 years ago
Read 2 more answers
39.6 x 5.20 show your work traditional method
fgiga [73]

Answer:


We have to multiply

⇒39.6 x 5.20 [ Using traditional method]

Traditional method: used by humans when they learnt counting and when fraction came into existence.Suppose something(Area of a field) is divided into parts and another thing(Amount of water used in irrigating the field) is divided into parts and then we have to multiply these two numbers.


3 0
3 years ago
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