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ahrayia [7]
3 years ago
14

A function f^-1 (x) contain the points (-2,3), (0,-1), (2,2), and (4,6). give the points known to be in the function of f(x).

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
4 0
(-1,0),(2,2),(3,-2),(6,4)
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Mariah makes bead necklaces. Beads are packaged in bags of 50 and bags of 200. Mariah bought 4 bags of 50 beads and 3 bags of 20
nalin [4]
Since she bought 4 bags of 50 beads and 3 bags of 200 beads you only need to use two operations: multiply and add. 4 x 50 is 200 3 x 200 is 600 600 + 200 = 800 Mariah purchase 800 beads in total.
6 0
2 years ago
Read 2 more answers
1 - (2n + 9) = 4(1-2)
Vikki [24]

Answer:

n=-2

Step-by-step explanation:

1−(2n+9)=4(1−2)

1+−1(2n+9)=4(1−2)

1+−1(2n)+(−1)(9)=4(1−2)

1+−2n+−9=4(1−2)

1+−2n+−9=−4

(−2n)+(1+−9)=−4

−2n+−8=−4

−2n−8=−4

−2n−8+8=−4+8

−2n=4

Divide both sides by -2

-2n/2=4/-2

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6 0
3 years ago
Read 2 more answers
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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(4*-2)-(-2*8)=
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