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denis-greek [22]
3 years ago
11

Give answer for this question ❓​

Mathematics
1 answer:
rjkz [21]3 years ago
7 0

Answer:

A. True

B. False

Step-by-step explanation:

B is false because rational numbers have either repeating decimals or numbers that come to an end.

You might be interested in
Please help me on this!
yanalaym [24]

Answer:

{9}^{ - 8}

Step-by-step explanation:

\frac{ {9}^{ - 5} }{ {9}^{3} }

{9}^{ - 5 - (3)}

{9}^{ - 5 +  (- 3)}

{9}^{  - 8}

6 0
3 years ago
Find the centre and radius for this circle , x^2+y^2=25
aliya0001 [1]

Answer:

centre = (0, 0 ), radius = 5

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

x² + y² = 25 ← is in this form

with centre = (0, 0 ) and r = \sqrt{25} = 5

3 0
3 years ago
8 There are a combined 33 students who play a spring sport of track or
Rzqust [24]

The number of students that are on the track team are 18.

The number of students that are on the baseball team are 15.

<h3>What are the linear equations that represent the question?</h3>

a + b = 33 equation 1

a - b = 3 equation 2

Where:

  • a = number of students that are on the track team
  • b = number of students that are on the baseball team

<h3>How many students that are on the baseball team?</h3>

Subtract equation 2 from equation 1

2b = 30

Divide both sides by 2

b = 30/2 = 15

<h3>How many students that are on the track team?</h3>

Subtract 15 from 33: 33 - 15 = 18

To learn more about simultaneous equations, please check: brainly.com/question/25875552

#SPJ1

8 0
2 years ago
The number of transistors per IC in 1972 seems to be about 4,000 (a rough estimate by eye). Using this estimate and Moore's Law,
spayn [35]

Answer:

The prediction for the number of transistor per IC in 1992 is of 4,194,304,000

Step-by-step explanation:

Moore's law:

Moore's law states that the number of transistors per IC doubles every year.

Format of the function:

Following Moore's law, t years after our initial estimative, the number of transistors per IC will be given by:

N(t) = N(0)*2^t

In which N(0) is the initial estimate.

The number of transistors per IC in 1972 seems to be about 4,000 (a rough estimate by eye).

This means that N(0) = 4000

So

N(t) = 4000*2^t

What would you predict the number of transistors per IC to be 20 years later, in 1992?

This is N(20). So

N(20) = 4000*2^20 = 4194304000

The prediction for the number of transistor per IC in 1992 is of 4,194,304,000

4 0
3 years ago
An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th
butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that \pi = 0.2

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}

0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}

\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}

(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}

n = 5615

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now \pi = 0.12, n = 5615.

We have to find M.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 2.81\sqrt{\frac{0.12*0.88}{5615}}

M = 0.012

7 0
3 years ago
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