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slava [35]
3 years ago
6

Pls help so I did tournament with my friend the placement is 1st-1250th and we got top 27% what does that mean-

Mathematics
1 answer:
Vesnalui [34]3 years ago
6 0

Answer:

1st place through 1250th. 1250 Divided by top 27% = 337.5

Step-by-step explanation:

Hope this helps! Have a great day

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An athlete trains on a circular track of radius 40 m and jogs 10 laps each day, 5 days a week. How far does he jog each week? Ro
mariarad [96]
Length of a circle=2πr
r=40 m
Length of the circular track=2*π*40m=80π m.

The athelete jogs each day 10 laps
1 lap-------------------80π m
10 laps-------------   x
x=(10 laps * 80π m) / 1 lap=800π m

Calculate how far he jog eache week (5 days).
1 day------------------800π m
5 days----------------   x
x=(5 days*800π m)/1day=4000π m=4000m * 3.141592...≈12566,37 m

solution: 12566 m

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If A is at (0,-8) and B is at (2,-4), what are the coordinates of C?
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Answer:

the answer is 4, 0

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What is the area of a rectangle with the length of 43 inches and a width of 25 inches?
Lorico [155]
1.72 is the area to the rectangle 
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State the degree for the polynomial:
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4

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the degree of the polynomial is the highest degree of any of the terms.

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) The density of oil in a circular oil slick on the surface of the ocean at a distance of r meters from the center of the slick
Feliz [49]

Answer:

Therefore the mass of the of the oil is 409.59 kg.

Step-by-step explanation:

Let us consider a circular disk. The inner radius of the disk be r and the outer diameter of the disk be (r+Δr).

The area of the disk

=The area of the outer circle - The area of the inner circle

= \pi (r+\triangle r)^2- \pi r^2

=\pi [r^2+2r\triangle r+(\triangle r)^2-r^2]

=\pi [2r\triangle r+(\triangle r)^2]

Since (Δr)² is very small, So it is ignorable.

∴A=2\pi r\triangle r

The density \delta (r)= \frac{40}{1+r^2}

We know,

Mass= Area× density

        =(2r \pi \triangle r)(\frac{40}{1+r^2}})

Total mass M=\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i

Therefore

\sum_{i=1}^n \frac{80r_i\pi }{1+r^2}\triangle r_i=\int_0^5 \frac{80r\pi }{1+r^2}dr

                      =40\pi[ln(1+r^2)]_0^5

                      =40\pi [ln(1+5^2)-ln(1+0^2)]

                     =40\pi ln(26)

                     = 409.59 kg (approx)

Therefore the mass of the of the oil is 409.59 kg.

3 0
2 years ago
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