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bazaltina [42]
4 years ago
10

Information is given about a polynomial f left parenthesis x right parenthesisf(x) whose coefficients are real numbers. find the

remaining zeros of f. degree​ 3; ​ zeros: negative 8 comma negative 3 minus i−8, −3−i enter the remaining zeros of f.
Mathematics
1 answer:
vazorg [7]4 years ago
5 0
A polynomial with real coefficients has either real zeros or conjugate pairs of complex zeros. A degree-3 polynomial will have 3 zeros. The one not listed is the conjugate of the complex zero listed.

The remaining zero of f(x) is -3+i.
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Answer:

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Step-by-step explanation:

<u>The Volume of Rectangular Prism</u>

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V = WHL

We are given the volume of a rectangular prism:

V=72x^8y^{14}z^{22}

It's also known the width is:

W=6x^3y

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H=3xy^5z^{10}

Substituting in the formula, we solve for L:

72x^8y^{14}z^{22}=(6x^3y)*(3xy^5z^{10})L

\displaystyle L=\frac{72x^8y^{14}z^{22}}{(6x^3y)*(3xy^5z^{10})}

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\displaystyle L=\frac{78x^8y^{14}z^{22}}{18x^4y^6z^{10}}

Dividing:

\displaystyle L=4x^{8-4}y^{14-6}z^{22-10}

Simplifying:

\boxed{\displaystyle L=4x^{4}y^{8}z^{12}}

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3 years ago
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Nata [24]
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Step2247 [10]

Answer:

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Step-by-step explanation:

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Vladimir79 [104]

Answer: \frac{2}{25} is the solution.

Step-by-step explanation;

Apply the property of fractions. Multiply the numerator with the numerator (1*2) and then the denominator with the denominator (5*5). This will give you: \frac{2}{25}.

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Answer:

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