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3 years ago

6

Please help me with this, I am stu pid. UnU

1 answer:

gladu [14]3 years ago

4 0

I’m pretty sure it’s c

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_____ > -2°C select one -3,0,-2.5,-5

ryzh [129]

Zero is greater than 2, so second one from the left.

3 0

3 years ago

Rename numbers 50 ten thousands

N76 [4]

50,000 would be 50 ten thousands

5 0

3 years ago

A multiple choice exam has ten questions. Each question has five possible answers, of which one is correct. Suppose that a stude

Ber [7]

Answer:

8.81% probability that the student answers exactly 4 questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A multiple choice exam has ten questions.

This means that $n = 10$

The probability of answering any question correctly is 0.20.

This means that $p = 0.2$

What is the probability that the student answers exactly 4 questions correctly

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{10,4}.(0.2)^{4}.(0.8)^{6} = 0.0881$

8.81% probability that the student answers exactly 4 questions correctly

4 0

4 years ago

Of all the employees,what is the approximate relative frequency of Managers who worked more than 40 hours ?

elena-14-01-66 [18.8K]

Answer:

The approximate relative frequency of Managers who worked more than 40 hours will be $9.3\%$ .

Step-by-step explanation:

The complete question is mentioned below in the attached diagram.

From the question diagram which is attached below, it is clear that

there are total $86$ employees, and

there are $8$ are who work more than $40$ hours per week.

Hence, the approximate relative frequency of managers who worked more than 40 hours will be:

$\frac{8}{86}=0.093$

Which is is equal to $9.3\%$ .

Therefore, the approximate relative frequency of Managers who worked more than 40 hours will be $9.3\%$ .

5 0

3 years ago

What is 7.2% of 3000

uysha [10]

$\displaystyle x= 7.2\% \ of \ 3000 \\ \\ x= \frac{7.2}{1\not00} \cdot 30\not00 .\\ \\ \\ x=7.2 \cdot 30 \\ \\ x=216$

3 0

4 years ago