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jekas [21]
3 years ago
9

√10 Multiple √15 is equal to

Mathematics
1 answer:
Paul [167]3 years ago
8 0

\\ \sf\longmapsto \sqrt{10}\times \sqrt{15}

\\ \sf\longmapsto \sqrt{10\times 15}

\\ \sf\longmapsto \sqrt{2\times 5\times  3\times 5}

\\ \sf\longmapsto \sqrt{5\times 5\times 6}

\\ \sf\longmapsto 5\sqrt{6}

None of the above should be 4th option

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Step-by-step explanation:

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Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
Help for good luck<br> and a lot of money
Alex777 [14]
1= 12.2
8=97.6
and for the last one the answer is 10 :))
5 0
2 years ago
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