V/2 + 65 = 6V/7
Multiply by 14
7V + 910 = 12V
910 = 5V
V = 182
so the answer is 182
( if you want to write a fraction put / like ( 1/2), Thanks!
Answer: the two trains will meet in 2.8 hours
Step-by-step explanation:
Step 1
Speed of train A = 90mph
Speed of train B = 110 mph
Since both trains are travelling towards each other
, their effective speed will be= 90 mph + 110mph= 200mph
Step 2
we know that Speed = distance / time
therefore Time = Distance / speed
Distance = 560 miles
Speed = 200 mph
Time = 560miles / 200mph
2.8 hours
I cant help you here. I am bad at math!!!
Yes it is possible. Consider the following scenarios
Scenario A:
Min = 5
Q1 = 10
Median = 12
Q3 = 18
Max = 22
The IQR is equal to the difference of Q3 and Q1
IQR = Q3-Q1 = 18-10 = 8
The range is the difference of the min and max
Range = Max - Min = 22 - 5 = 17
So in summary for scenario A, we have
IQR = 8
Range = 17
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Now consider another scenario, call it scenario B, where
Min = 100
Q1 = 102
Median = 105
Q3 = 110
Max = 117
I claim that the IQR and Range for scenario B is going to be the same as in Scenario A. Let's find out
IQR = Q3 - Q1 = 110 - 102 = 8
Range = Max - Min = 117 - 100 = 17
So
IQR = 8
Range = 17
which is identical to scenario A.
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Scenario B has completely different data than scenario A, yet the IQR and Range are equal to scenario A's counterparts. This shows that it is possible to have 2 completely sets of data yet have the same IQR and range.
The wrap up here, and the answer to the question, is "yes it is possible" with the explanation given above.
I think that she wouldn't end up with “$14,400” she would end up with $76,800 if you multiply.
