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nevsk [136]
3 years ago
9

PLEASE PLEASE HELP!! (numbers in drop down menu are the same options for all of the x values)

Mathematics
1 answer:
zubka84 [21]3 years ago
4 0

Answer:

1) for -1 as x, k(x) would be -8

2) for -3 as x, k(x) would be -18

3) for 0 as x, k(x) would be -3

4) for 1 as x, k(x) would be 2

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LaTesha and Bernard are playing a game. Their scores for five games are shown in the table below. LaTesha’s and Bernard’s Scores
andre [41]

Answer:

The means differ by 1, but the ranges differ by 40.

Step-by-step explanation:

The mean for LaTesha's score is (92+45+67+36+80)/5= 64

The mean for Benards score is (63+68+62+69+53)/5= 63

The range for LaTeshas score is 92-36=56

The range for Benards score is 69-53=16

So, 64-63=1     and        56-16= 40

6 0
3 years ago
A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is
tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form  has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that  n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

4 0
3 years ago
5cosx -2sin(x/2) +7=0<br>Help me to find x step by step<br>pls​
miskamm [114]

Answer:

x = 180

Step-by-step explanation:

First, you need to know

1. Double-angle formula:

cos(2x) = cos^{2}x - sin^{2}x

2. Pythagorean identity:

cos^{2}x + sin^{2}x = 1

Back to your problem, replacing the variable by the above:

5cosx-sin\frac{x}{2}+7 = 0

5(cos^{2}\frac{x}{2}-sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0 By Double-angle formula

5(1 - 2sin^{2}\frac{x}{2}) - 2sin\frac{x}{2} + 7 = 0 By Pythagorean identity

Given y = \frac{x}{2}

5(1-2sin^{2}y) - 2siny + 7 = 0

10sin^{2}y+2siny-12=0

5sin^{2}y+siny-6=0

(5siny + 6)(siny - 1)=0, we know -1 < sinx < 1, for every x ∈ R

siny = 1, y =90

y = \frac{x}{2}

x = 180

8 0
3 years ago
What would be the best estimate for the height of a front door?
solmaris [256]

Answer: The height of a standard door is about 2 m. The length of an adult pace is about 1 m. The length of a size 8 shoe is about 30 cm. Most adults are between 1.5 m and 1.8 m in height.

Step-by-step explanation:

5 0
3 years ago
PLEASEEEEE help!!!!!!!!!!!!
Yuliya22 [10]

Answer:

2st

Step-by-step explanation:

because only 34 can be divided by 17 and there arent enough of s and ts

6 0
2 years ago
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