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Kitty [74]
3 years ago
5

How do you solve this?

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

Triangles ABC and LBM are similar. We know this because AL and LB have the same length, so that AB is twice as long as either AL or LB. The same goes for MC and BM, and BC. The angle B is the same for both tirangles ABC and LBM, so the side-angle-side postulate tells us the triangles are similar, and in particular that triangle ABC is twice as large as LBM.

All this to say that LM must be half as long as AC, so LM has length (B) 14 cm.

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Find the value of x in the figure below. <br> 26<br> 56<br> Х
SashulF [63]
The answer is 30

Explanation:

So all of the angles in a triangle add up to 180 degrees and so if you split the triangle into separate triangles then you can add up the angles that are known and subtract from 180 to get the size of the missing angle e.g 90 + 56 = 146, 180 -146 = 34 for the other triangle 90 + 26 = 116, 180 - 116 = 64 and so 64 - 34 = 30
4 0
3 years ago
Lynn is 4 years younger than her sister Tobbe. If the sum of their ages is 18, how old are Lynn and Tobbe?
expeople1 [14]
Lynn is 7, Tobbe is 11.. Go get a Slurpee now
5 0
3 years ago
Read 2 more answers
draw an example of a shape that has at least one right angle one angle less than a right angle and one angle greater than a righ
MaRussiya [10]
That is not possible to make a triangle with a right angle and a acute angle because a acute triangle only has acute angles and a right triangle has a obtuse angle in it
3 0
3 years ago
Answer number 1 please.​
Minchanka [31]

\sf {a}^{2}  =  {13}^{2}  -  {5}^{2}

Formula :

Base²= Hypotenuse² - Perpendicular ²

\\  \\

\hookrightarrow\sf {a}^{2}  =  {13}^{2}  -  {5}^{2}

\\  \\

\hookrightarrow\sf {a}^{2}  =169 - 25

\\  \\

\hookrightarrow\sf {a}^{2}  =144

\\  \\

\hookrightarrow\sf {a} = \sqrt{144}

\\  \\

\hookrightarrow\sf {a} = \sqrt{12 \times 12}

\\  \\

\hookrightarrow\sf {a} = 12

Remember the a² in formula has nothing to do with the a we have to find. :)

6 0
2 years ago
Read 2 more answers
In the diagram below AFB is congruent to EFD if EFD = 5x + 6, DFC = 19x - 15, and EFC = 17x + 19, find AFE
yanalaym [24]

The angle m∠AFE is 128 degrees.

<h3>How to find angles?</h3>

∠AFB ≅ ∠EFD

∠EFD = 5x + 6

m∠DFC = (19x - 15)°

m∠EFC = (17x + 19)°

m∠AFE = ?

m∠AFB + m ∠EFD + m∠AFE = 180

Therefore,

5x + 6 + 5x + 6 + m∠AFE = 180

5x + 5x + 6 + 6 + m∠AFE = 180

10x + 12 + m∠AFE = 180

10x + m∠AFE = 180 - 12

10x + m∠AFE  = 168

m∠AFE = 168 - 10x

m∠EFC =  m ∠EFD + m∠DFC

17x + 19 = 5x + 6 + 19x - 15

17x - 5x - 19x = 6 - 15 - 19

-7x = - 28

x = 28 / 7

x = 4

Therefore,

m∠AFE = 168 - 10x

m∠AFE = 168 - 10(4)

m∠AFE = 168 - 40

m∠AFE = 128°

Therefore, the angle m∠AFE = 128°

learn more on angles here: brainly.com/question/13212279

#SPJ1

7 0
2 years ago
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