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slega [8]
3 years ago
11

Help please and thank you

Mathematics
1 answer:
aksik [14]3 years ago
5 0
Remember
(a^b)^c=a^{bc}
and
\frac{x^a}{x^b}=x^{a-b}


so

\frac{(7^2)^5}{7^{-6}}=
\frac{7^{2*5}}{7^{-6}}=
\frac{7^{10}}{7^{-6}}=
7^{10-(-6)}=
7^{10+6}=
7^{16}

the answer is D
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What is the slope and what is the y intercept of y=<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B4%7D%20" id="TexFormula
WARRIOR [948]
<span> [ x = -9 i think ok hop it helps you</span>
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3 years ago
Read 2 more answers
Find the missing side. Round to the nearest 10th.
const2013 [10]

Answer:

5.0

Step-by-step explanation:

Using Pythagorean Theorem:

a² + b² = c²

where a =? b= 12 in and c = 13 in

a² + (12)² = (13)²

a² + 144 = 169

a² = 169 - 144

a² = 25

a = √25 = 5

∴ a = 5.0

Pythagoras Theorem is usually applied when finding one missing side of a right-angle triangle.

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3 years ago
Convert 3.06% as a decimal and a fraction in simplest form
Volgvan
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Hope this helped!
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3 years ago
Oscars aunt leaves 50 miles away , this is 6 times times as far
Leno4ka [110]
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2 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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