Question

What is an equation of the line that passes through the points (-6, -8) and (-3,-3)?​

Answer 1

Answer:

y = 5/3x+2

Step-by-step explanation:

First find the slope

m = ( y2-y1)/(x2-x1)

   = ( -3 - -8)/( -3 - -6)

    = ( -3+8) / (-3+6)

    = 5/3

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

Substituting the point (-3,-3)

-3 = 5/3(-3) + b

-3 = -5+b

-3+5 = b

2 = b

y = 5/3x+2

Answer 2

Given points

• (-6,-8)
• (-3,-3)

First find the slope

$\boxed{\sf m=\dfrac{y_2-y_1}{x_2-x_1}}$

$\\ \sf\longmapsto m=\dfrac{-3+8}{-3+6}$

$\\ \sf\longmapsto m=\dfrac{5}{3}$

Now

$\boxed{\sf y=mx+b}$

$\\ \sf\longmapsto -3=\dfrac{5}{3}(-3)+b$

$\\ \sf\longmapsto b=2$

Hence the equation will be

$\\ \sf\longmapsto y=\dfrac{5}{3}x+2$