We have been given that John's commute time to work during the week follows the normal probability distribution with a mean time of 26.7 minutes and a standard deviation of 5.1 minutes.

We are asked to find the probability that the commute time for a randomly selected day will be between 28 and 34 minutes.

First of all, we will find z-score corresponding to 28 minutes and 34 minutes. Then, we will find area under normal curve between both z-scores.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{28-26.7}{5.1}=\frac{1.3}{5.1}=0.25$

$z=\frac{34-26.7}{5.1}=\frac{7.3}{5.1}=1.43$

Now, we need to find the probability between z-score of 1.43 and 0.25.

$P(0.25$ .

Using formula $P(a$ , we will get:

$P(0.25$

Therefore, the probability, that the commute time for a randomly selected day will be between 28 and 34 minutes, is 0.32493.

6 0

3 years ago

Santa has 300 he share. 1/5 3/10 50.00 he bank the rest what fraction did he bank

Black_prince [1.1K]

Answer:

1/6

Step-by-step explanation:

$50 is 1/6 of $300

(I think this is what you meant. The question was kind of confusing.)

4 0

3 years ago