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TEA [102]
3 years ago
9

What is the area of the trapezoid?

Mathematics
1 answer:
storchak [24]3 years ago
7 0

Answer:

A = 70 mm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h (b₁ + b₂)

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 10, b₁ = 10, b₂ = 4 , then

A = \frac{1}{2} × 10 × (10 + 4) = 5 × 14 = 70 mm²

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The sum of two consecutive integers is 139, find the integers.
Ad libitum [116K]
They would be 69 and 70.

Your equation would be x + (x + 1) = 139

X would be the first integer and x + 1 would be the second

You would then solve the equation to get x as 69

X + 1 would then be 70
7 0
3 years ago
What is the dimension of a rectangle if the perimeter is 198
AfilCa [17]

Answer:

Length = 49.5 unit and width = 49.5 unit

Step-by-step explanation:

Given as , Perimeter of rectangle = 198 unit

so ,as Perimeter of rectangle = 2× ( Length + width)

Or,                                   198 = 2 ×  (Length + width)

Or,                                   \frac{198}{2} = length + width

So, length + width = 99 unit

Now to make area maximum

Length × width = maximum

Or, (99 - width ) × width = maximum

      99 Width - width² = maximum                              Let width = W

Now differentiate both side with respect to W

D(99W - W²)\frac{D(99w - w^2)}{Dw} = 0         as, constant diff is 0

So, 99 - 2w = 0

Or, w = \frac{99}{2}

Or, w = 49.5 unit    and L = 99- 4905 = 49.5 unit      Answer

3 0
3 years ago
At most, how many unique roots will a third-degree polynomial function have?
beks73 [17]

The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.

In fact, if you use complex number, then a polynomial with degree n has exactly n roots.

So, in particular, a third-degree polynomial can have at most 3 roots.

In fact, in general, if the polynomial p(x) has solutions x_1,\ x_2,\ldots x_n, then you can factor it as

p(x) = (x-x_1)(x-x_2)\ldots (x-x_n)

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

p(x)=(x-x_1)(x-x_2)(x-x_3)(x-x_4)

But this is a fourth-degree polynomial.

7 0
3 years ago
A letter is selected at random from each of the words, Sure and WIN. Find
Orlov [11]

Answer:

a) 1/8 b) 1/6

Step-by-step explanation:

b) 6/36 = 1/6

a) 1/2 x 1/2 x 1/2 = 1/8

7 0
2 years ago
Read 2 more answers
TWO QUESTIONS PLS HELP ASAP
ASHA 777 [7]
Answer: 4. (-1,-1) 3. (3,-2)

4)

Set the equations equal to each other.

4x+3=-x-2

Subtract 3 from both sides

4x=-x-5

Add x to both sides

5x=-5

Divide both sides by 5

x=-1

Next, replace x with -1 in either equation to find y.

-(-1)-2=y

-1=y


3)

Do the same thing for this one and set them equal to each other

-2x+4=-1/3x-1

Add 1 to both sides

-2x+5=-1/3x

Add 2x to both sides

5=5/3x

Divide both sides by 5/3

x=3

Next, replace x with 3 in either equation

-2(3)+4=y

-2=y




4 0
3 years ago
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