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den301095 [7]
3 years ago
14

TWO QUESTIONS PLS HELP ASAP

Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0
Answer: 4. (-1,-1) 3. (3,-2)

4)

Set the equations equal to each other.

4x+3=-x-2

Subtract 3 from both sides

4x=-x-5

Add x to both sides

5x=-5

Divide both sides by 5

x=-1

Next, replace x with -1 in either equation to find y.

-(-1)-2=y

-1=y


3)

Do the same thing for this one and set them equal to each other

-2x+4=-1/3x-1

Add 1 to both sides

-2x+5=-1/3x

Add 2x to both sides

5=5/3x

Divide both sides by 5/3

x=3

Next, replace x with 3 in either equation

-2(3)+4=y

-2=y




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Choose the most appropriate strategy and then use it to solve the quadratic equation.
dsp73

 (x-8) ^ 2 = 121
 
(x-8) = + / - root (121)
 x = 8 +/- root (121)
 The solutions are:
 
x1 = 8 + root (121)
 
x2 = 8 - root (121)
 2a ^ 2 = 8a-6
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 x ^ 2 + 12x + 36 = 4
 x ^ 2 + 12x + 36-4 = 0
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7 0
3 years ago
What is the value of m in the equation 4m + 2(m + 1) = 9m + 5? <br> −1<br> 1<br> 7<br> 17
ozzi

4m +2(m+1) = 9m +5

4m +2m+2 = 9m +5

6m +2 = 9m +5

6m = 9m+3

-3m = 3

m = -1

4 0
3 years ago
Read 2 more answers
Help please will mark brainliest!!!
Daniel [21]

Answer:

45°

Step-by-step explanation:

Well, compared to 90°, it looks like it's just smaller, but not too small. It couldn't be 15° degrees, or 60°, as it was probably too much. I Don't think it's 30° either,  because it looked bigger than what a 30° angle would be.

Hope it helped!

~Flip

7 0
3 years ago
What radical expression is not simplified?
rodikova [14]
B 2/10 is not simplified because you can divide each number by 2 reducing it to 1/5.
5 0
3 years ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
4 years ago
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