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topjm [15]
3 years ago
15

If ella earns x dollars, she is taxed x%. How much money should she earn to maximize her income?

Mathematics
1 answer:
aev [14]3 years ago
5 0

Answer:

just devide it. after that ÷ with 100 per time

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And a picture of a charger just because
REY [17]

Answer:

1. 1

2. 5

3. lost 0.8 pounds

Step-by-step explanation:

The least value (or the most she lost) is in week 1

The greatest value (or the most she gained) is in week 5

When you add all the values together, you get:

-4.1 (lost)

3.3 (gained)

3.3 - 4.1 = -0.8

She lost a total of 0.8 pounds

These are your answers

Hope this helps!

5 0
3 years ago
Pls solve the last box I don’t understand it. Thnx :)
Pavel [41]

Answer:

(0, -3) and (2, 1)

Step-by-step explanation:

There are 5 points marked on the graph: (±2, 1), (±1, -2) and (0, -3). These are solutions to the equation describing the function:

... y = x² - 3

Apparently, you are being asked to report the coordinates of any two of these points.

_____

<em>Comment on the problem</em>

The wording "solutions to the function" is a bit odd. An equation has solutions—values of the variables that make it be true. A function is a relationship between values, a definition. There is nothing  to solve.

In the above we have assumed the intent is to find (x, y) pairs that match the function definition. Sometimes, we're interested in values of x that make y be zero. (x, y) = (±√3, 0) It isn't obvious what the intent of this question is.

8 0
3 years ago
Express 9 -² using positive exponents. Do not simplify.
Leokris [45]
1/9^2 if that makes sense?
3 0
2 years ago
I dont get iiiittttt <br> please help 40 points
julia-pushkina [17]

Answer:

15/28

Step-by-step explanation:

____________________________

7 0
3 years ago
Read 2 more answers
He number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the
denis-greek [22]

The function that represents the number of E.coli bacteria cells per 100 mL of water as t years elapses, and is missing in the question, is:

A(t)=136(1.123)^{4t}

Answer:

   Option A. 59%

Explanation:

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function::

  • A(t)=136(1.123)^{4t}

  • rate=(1.123)^{4t}=(1.123)^4=1.590

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

You can calculate it also using two consecutive values for t. For instance, use t =1 and t = 1

t=1\\\\ A(1)=136(1.123)^4\\\\\\t=2\\ \\ \\A(2)=136(1.123)^8\\ \\ \\A(2)/A(1)=1.123^8/1.1123^4=1.123^4=1.590

6 0
3 years ago
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