The second one write it on the paper and take a picture

Mathematics

2 answers:

Elodia [21]2 years ago

6 0

Answer:

The common for the second question is 30

Sati [7]2 years ago

6 0

Answer:

39/30 Here 30 will be common in denominators

Step-by-step explanation:

6/15×2/2=12/30

3/10×3/3=9/30

3/5×6/6=18/30

= 12/30+9/30+18/30

39/30

You might be interested in

Please help me....I really need help!!

scoundrel [369]

$\dfrac{c^2-4}{6c^4+15c^3}\div\dfrac{c^2+4c+4}{12c^3+30c^2}=\dfrac{c^2-2^2}{3c^3(2c+5)}\div\dfrac{c^2+2(c)(2)+2^2}{6c^2(2c+5)}\\\\_{\text{use}\ a^2-b^2=(a-b)(a+b)\ \text{and}\ (a+b)^2=a^2+2ab+b^2}\\\\=\dfrac{(c-2)(c+2)}{3c^3(2c+5)}\cdot\dfrac{6c^2(2c+5)}{(c+2)^2}=\dfrac{(c-2)}{c}\cdot\dfrac{2}{(c+2)}=\boxed{\dfrac{2(c-2)}{c(c+2)}}$

6 0

3 years ago

The weight of a bull clad is 388 kilograms. If it’s weight increases at a rate of 1 2/5 kilograms per day how long it will take

Alex73 [517]

Answer:

It will take 80 days for the bull calf to reach a weight of 500 kilograms.

Step-by-step explanation:

Given:

The weight of a bull calf is 388 kilograms.

Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.

Required weight which to be increased = 500 - 388 = 112 kilograms.

Rate of weight increase = $1\frac{2}{5}=\frac{7}{5}$