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olga55 [171]
3 years ago
14

Please help me with this question:)

Mathematics
1 answer:
tester [92]3 years ago
3 0

Answer:

Ada is correct.

Step-by-step explanation:

Problems with Naman:

Naman is supposed to follow PEMDAS, which is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Division

Addition

Subtraction

~

The mistake: Naman moved +6 to the left and added it to the 2 located on the left side of the expression. You cannot do that, as it breaks the law of PEMDAS. On the other hand, Ada did the correct thing, which was to distribute 2 to all terms within the parenthesis (as one term in the parenthesis has a variable, and the other is a constant, meaning that they cannot be combined). This leads to Naman not doing the rest of the question correct.

Next, Ada correctly combined the two constants, which resulted in 0. 0 means nothing, therefore the placeholder is not needed. Therefore, 8x is the final answer.

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Item 15 Question 1 Show that quadrilateral WXYZ with vertices W(−1,6), X(2, 8), Y(1, 0), and Z(−2,−2) is a parallelogram by find
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Answer:

Multiple answers

Step-by-step explanation:

A parallelogram is a flat shape that has four sides. The two sets of opposite sides are parallel and of equal length to each other.

To prove that our figure is a parallelogram we first get the slope of our sides.

The formule we use to get the slope is:

m = \frac{y-y1}{x-x1}

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if we use our formule to calculate the slope of W-Z:

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if we use our formule to calculate the slope of X-Y:

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2. Then we have the W-X side that it's supossed to be parallel to Z-Y side

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if we use our formule to calculate the slope of Z-Y:

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  • We know that parallel lines will never intersect because they have the same slope, therefore W-X side is parallel to Z-Y side

Then we have to prove that the parallalel sides are equal length to each other.

The formule we use to get the distance between two points is:

\sqrt{(x2-x1)^{2}+(y2-y1)^{2}  }

We calculate the lenght of the W-Z side that it's supossed to be equal to X-Y side:

W-Z = \sqrt{(-1-(-2))^{2}+(6-(-2))^{2}  } =   \sqrt{65}

X-Y = \sqrt{(2-1)^{2}+(8-0)^{2}  } = \sqrt{65}

So the W-Z side have the same lenght to X-Y side.

We calculate the lenght of the W-X side that it's supossed to be equal to Z-Y side:

W-X = \sqrt{(-1-2)^{2}+(6-8)^{2}  } =   \sqrt{13}

Z-Y = \sqrt{(-2-1)^{2}+(-2-0)^{2}  } = \sqrt{13}

So the W-X side have the same lenght to Z-Y side.

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