The solution to the equation is x < 1.25
LCD (1/7, 14/7, 12/13, 5/6)
LCM = (7, 7, 13, 6)
= 2 * 3 * 7 * 13
= 546
1/7 = 78/546
14/7 = 1092/546
12/13 = 504/546
5/6 = 455/546
Calculation:
1/7 + 14/7
= 1 + 14/7
= 15/7
The common denominator you can calculate as the least common multiple of the both denominators: LCM (7, 7) = 7
Add:
15/7 + 12/13
= 15 . 13/7. 13 + 12 . 7/13 . 7
= 195/91 + 84/91
= 195 + 84/91
= 279/91
The common denominator you can calculate as the least common multiple of the both denominators: LCM (7, 13) = 91
Add:
279/91 + 5/6
= 279 . 6/91 . 6 + 5 . 91/6. 91
= 1674/546 + 455/546
= 1674 + 455/546
= 2129/546
The common denominator you can calculate as the least common multiple of the both denominators: LCM (91, 6) = 546
Hence, 546 is the LCM/LCD of (1/7, 14/17, 13/13, 5/6).
Hope that helps!!!!!!
Answer:
16 : 100 = 8 : 50 = 4 : 25
Step-by-step explanation:
You just half each side by the same number
Answer:
x=7
Step-by-step explanation:
f(x) =g(x)
12-2=x+3
10=x+3
10-3=x
x=7
Answer:
B. Train B
Step-by-step explanation:
We are told that Milford and Pinkerton is 300 miles away.
Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.
Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.
Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.
Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.
