The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the
1 answer:
Answer:
Step-by-step explanation:
I'm assuming that the length of the spring is s and the mass of the object is m. If that be the case, the direct variation equation, which a line btw, is
s = km where k is the constant of proportionality. We have to solve for k, the slope of the line, in order to determine the model for this situation.
9 = k(30) so
Now that we know, the slope of the line, we can rewrite the equation with the slope in place:
, choice A.
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Given:
The equation of a circle is
A tangent line l to the circle touches the circle at point P(1,3).
To find:
The equation of the line l.
Solution:
Slope formula: If a line passes through two points, then the slope of the line is
Endpoints of the radius are O(0,0) and P(1,3). So, the slope of radius is
We know that the radius of a circle is always perpendicular to the tangent at the point of tangency.
Product of slopes of two perpendicular lines is always -1.
Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.
The slope of line l is and it passs through the point P(1,3). So, the equation of line l is
Adding 3 on both sides, we get
Therefore, the equation of line l is .