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3 years ago

(PLEASE ANSWER ASAP I JUST NEED TO CHECK MY ANSWER PLEASE EXPLAIN ALSO)

Mathematics

2 answers:

Free_Kalibri [48]3 years ago

8 0

2.just subtract one from morning and half a hour is 30 minutes so it would be 2 hours left

ValentinkaMS [17]3 years ago

4 0

Answer:

1 hour and half an hour

Step-by-step explanation:

cause 3 hours minus 1 hour minus half an hour equal to 1 hour and half, hope this help u

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What is the probability of drawing a month that has 31 days?

jok3333 [9.3K]

Answer: 5/12

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3 years ago

A 16 -foot ladder is leaning on a tree. The bottom of the ladder on the ground at a distance of 6 feet from the base of the tree

Dima020 [189]

Answer:

14.8 feet

Step-by-step explanation:

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2 years ago

If k=[-4 | 2, 6 | -3] and m=[2 | 8, -2 | 5] what is x when 2x -k = m

marshall27 [118]

Answer:

x = [-1 | 5, 2 | 1]

Step-by-step explanation:

We assume your notation is used to describe 2×2 matrices.

Solve for x:

2x -k = m

2x = m + k . . . . add k

x = (1/2)(m +k) . . . . multiply by 1/2

Fill in the values:

x = 1/2[2+(-4) | 8 +2, -2+6 | 5+(-3)]

x = [-1 | 5, 2 | 1]

5 0

3 years ago

For f(x) = 0.01(2)x, find the average rate of change from x = 2 to x = 10.

kenny6666 [7]

$\bf slope = m = \cfrac{rise}{run} \implies 
\cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby 
\begin{array}{llll}
average~rate\\
of~change
\end{array}\\\\
-------------------------------\\\\
f(x)=0.01(2)^x \qquad 
\begin{cases}
x_1=2\\
x_2=10
\end{cases}\implies \cfrac{f(10)-f(2)}{10-2}
\\\\\\
\cfrac{0.01(2)^{10}~~-~~0.01(2)^2}{8}\implies \cfrac{10.24~~-~~0.04}{8}\\\\\\ \cfrac{10.20}{8}\implies 1.275$

7 0

4 years ago

Read 2 more answers

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

4 years ago