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slamgirl [31]
3 years ago
7

The common ratio of the geometric sequence -14,-84,-504

Mathematics
1 answer:
olga_2 [115]3 years ago
3 0

A common ratio is basically a ratio of next sequence and the sequence you want

To find a common ratio of geometric sequence, we usually define 'r' as common ratio.

\displaystyle \large \tt{r =  \frac{next  \:  \: sequence}{the \: \: sequence \:  \: you \:  \: want} }

For example, I want to focus on -14 and the next sequence would be -84.

Hence,

\displaystyle \large{r =  \frac{ - 84}{ - 14} }

Thus, r is 6 because both numerator and denominator are negative. negative divides negative = positive.

Or you want to choose -84, then the next sequence would be -504.

\displaystyle \large{r =  \frac{ - 504}{ - 84} }

Then r would still be 6. Since both ways have r as 6 and this proves that the sequence is geometric.

Hence, the common ratio is 6.

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Which statement about y = x2 + 7x - 30 is true?
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Answer:

D. The zeros are 3 and -10, because y = (x - 3)(x + 10).

Step-by-step explanation:

y=x^2+7x-30

0=x^2+7x-30

0=(x+10)(x-3)

Therefore, D is correct by the Zero Product Property

4 0
3 years ago
Simplify this expression; -15k-1+12+2k​
Arlecino [84]

Answer: -13k+11

Step-by-step explanation:

Combine like terms

-15k+2k=-13k

-1+12=11

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4 years ago
Dan bought a home theater system for $178.99 on the installment plan. The term of the contact said that he would pay $35 a month
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7 0
3 years ago
Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
Vsevolod [243]

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

Multiplication can be transformed into difference of squares using the rule: \sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

By definition, i² is -1. Calculate the denominator.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

Do the multiplications in \sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right).

\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

Combine the real and imaginary parts in -10+45i+6i+27.

\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

Do the additions in \sf-10+27+\left(45+6\right)i.

\large \bf Re(\frac{17+51i}{85})  \\

Divide 17+51i by 85 to get \sf\frac{1}{5}+\frac{3}{5}i \\.

\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

The real part of \sf \frac{1}{5}+\frac{3}{5}i \\ is \sf \frac{1}{5} \\.

\large  \boxed{\bf\frac{1}{5} = 0.2} \\

3 0
3 years ago
16 .Write an equation that represents the statement
Brums [2.3K]

Answer:

x-12=18

Step-by-step explanation:

7 0
3 years ago
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