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VLD [36.1K]
3 years ago
10

Solve for x: 3x²-243​

Mathematics
1 answer:
mylen [45]3 years ago
7 0

3x²–243=0 —> 3 (x²–81) = 0 —>

x²–81=0 —> (x-9)(x+9)=0

x-9=0 —> x=9

x+9=0 —> x=–9

I hope I helped you^_^

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Step 1: Write equation

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Combine the terms by multiplying into a single fraction.

\bf{\dfrac{5}{2}x-7=\dfrac{3}{4}x+14   }

Find the common denominator.

\bf{\dfrac{5x}{2}-7=\dfrac{3}{4}x+14   }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x(-7)}{2}=\dfrac{3}{4}x+14   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3}{4}x+14   }

Combine the multiplied terms into a single fraction

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+14   }

Find the common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+\dfrac{4\cdot14}{4}    }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+4\cdot14}{4}   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+56}{4}   }

Eliminate the denominators of the fractions.

\bf{4\cdot\dfrac{5x-14}{2}=4\cdot\dfrac{3x+56}{4}   }

Cancel the multiplied terms that are in the denominator.

\bf{2(5x-14)=3x+56}

To distribute.

\bf{10x-28=3x+56 }

Add 28 to both sides.

\bf{10x-28+28=3x+56+28 }

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\bf{10x-3x=3x+84-3x }

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Divide both sides by the same factor.

\bf{x=\dfrac{84}{7} }

Simplify

\bf{x=12 \ \ \ === > \ \ \ Answer}

↓

<h3>Verification</h3>

Let x=12.

  1. \bf{\dfrac{5}{2}\times12-7=\dfrac{3}{4}\times12+14   }
  2. \bf{\dfrac{5\times12}{2}-7=\dfrac{3}{4}\times12+14   }
  3. \bf{\dfrac{60}{2}-7=\dfrac{3}{4}\times12+14   }
  4. \bf{30-7=\dfrac{3}{4}\times12+14   }
  5. \bf{30-7=\dfrac{3\times12}{4}+14   }
  6. \bf{30-7=\dfrac{36}{4}+14   }
  7. \bf{30-7=9+14   }
  8. \bf{23=9+14 }
  9. \bf{23=23}

Checked ✅

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