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3 years ago

A piece of string is 1650 cm long.

Mathematics

2 answers:

balandron [24]3 years ago

4 0

Answer: The smaller piece is 750m long.

Step-by-step explanation:

let the smaller piece be x

150m + x + x = 1650

150 + 2x = 1650

or, 2x = 1500

so, x = 750 m

slavikrds [6]3 years ago

3 0

Step-by-step explanation:

Length of a piece of string= 1650cm

First piece (x)= 150 + second piece(y)

x=150+y

Total length

x+y=1650

150+2y=1650

2y=1500

y=750cm

Smaller piece length is 750cm

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Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

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$f(t)=0.4e^{-0.4t}$

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The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

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Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

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