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Bess [88]
3 years ago
7

The area of a square is defined by, A(x) = x 2 - 12x + 36. What is the length of a side of the square?

Mathematics
2 answers:
kumpel [21]3 years ago
8 0
<span>A(x) = x 2 - 12x + 36
</span><span>A(x) = (x -6)^2

answer: length of a side of the square = x - 6</span>
Maksim231197 [3]3 years ago
3 0

Answer: The required length of a side of the square is (x - 6) units.

Step-by-step explanation:  Given that the area of a square is as follows :

A(x)=x^2-12x+36~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We are to find the length of a side of the square.

We know that

all the sides of a square have equal length l, and its area is given by

A=l^2.

From expression (i), we have

A(x)\\\\=x^2-12x+36\\\\=x^2-2\times x\times 6+6^2\\\\=(x-6)^2.

Therefore, the required length of a side of the square is (x - 6) units.

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The perimeter is when you add all the sides of a shape. In a rectangle, two sides are the same, and so are the other two. So, if the two sides are 2x-3 and x+2 the expression will be: 

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Read 2 more answers
Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2
tigry1 [53]

Answer:

=-12

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Step-by-step explanation:

We are given that inner product defined on R_n

=3u_1v_1+u_2v_2

u=(0,-4),v=(5,3)

We have to find the value of <u,v> and d(u,v)

We have u_1=0,u_2=-4,v_1=5,v_2=3

Substitute the value then we get

=3(0\cdot5)+(-4)(3)=-12

Now, d(u,v)=\left \|v-u\right \|

Using this formula we get

d(u,v)=\left \| (5,7) \right \|=\sqrt{3(5)^2+(7)^2}=\sqrt{75+49}=\sqrt{124}

d(u,v)=2\sqrt{31}

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