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Tasya [4]
3 years ago
5

Determine the interval(s) on which the given function is decreasing.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0

A function is decreasing if, reading from left to right, we can see that the graph of the function goes down.

Here we can't see the graph, but we have a brief description.

"the graph goes up until it reaches a maximum at (0, 5), then the graph reaches a relative minimum at (1, 4), then it goes up again"

Now, the graph was going up until it reached the maximum, so at that point, the graph starts going down.

The graph will go downwards until it reaches the minimum, at that point the graph starts increasing again.

So the graph only goes down between x = 0 and x = 1.

we can conclude that the interval on which the given function is decreasing is [0, 1]

If you want to learn more, you can read:

brainly.com/question/21287583

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What is the coordinate?
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Remember that the equation of a circle is:
(x - h)^{2} + (y - k)^{2} =  r^{2}
Where (h, k) is the center and r is the radius.
We need to get the equation into that form, and find k.

x^{2} - 6x +  y^{2} - 10y = 56

Complete the square. We must do this for x² - 6x and y² - 10y separately.

x² - 6x
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Because we've added 9 on one side of the equation, we have to remember to do the same on the other side.

x^{2} - 6x + 9 + y^{2} - 10y = 65

Now factor x² - 6x + 9 to get (x - 3)² and do the same thing with y² - 10y.

y² - 10y
Divide -10 by 2 to get -5.
Square -5 to get 25.
Add 25 on both sides.

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Factor y² - 10y + 25 to get (y - 5)²

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Now our equation is in the correct form. We can easily see that h is 3 and k is 5. (not negative because the original equation has -h and -k so you must multiply -1 to it)

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