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3 years ago

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Annette drove through an intersection without looking and hit Vincent's car that he had driven into the intersection without obe

ying a stop sign. Annette sued Vincent. The jury found that Annette's fault contributed 20 percent to the collision and determined that her total loss was $100,000. Under comparative negligence, the jury should award Annette

1 answer:

Karolina [17]3 years ago

7 0

Answer:

$80,000

Step-by-step explanation:

Under a Comparative negligence theory, people involved in an accident are entitled to compensation according to their contributions towards the accident. In this case, Annette contributed 20% to the collision and, thus, should receive 100% - 20% of her total loss determined by the jury. Annette should be awarded:

$A= \$ 100,000*(1-0.2)\\A=\$ 80,000$

Therefore, the jury should award Annette $80,000

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A company is constructing an open-top, square-based, rectangular metal tank that will have a volume of 34.5 ft3. what dimensions

____ [38]

Answer:

$l \approx 3.3\,ft$ , $x = 3.2\,ft$

Step-by-step explanation:

The equations of volume and surface area are presented below:

$34.5 = l^{2}\cdot x$

$A_{s} = 2\cdot l^{2} + 4\cdot l \cdot x$

The length of the tank is:

$x = \frac{34.5}{l^{2}}$

The expression fo the surface area is therefore simplified into an univariable form:

$A_{s} = 2\cdot l^{2} + 4\cdot \left(\frac{34.5}{l} \right)$

$A_{s} = 2\cdot l^{2} + \frac{138}{l}$

The first and second derivatives of the expression are, respectively:

$A_{s}' = 4\cdot l -\frac{138}{l^{2}}$

$A_{s}'' = 4 +\frac{276}{l^{3}}$

The first derivative is equalized to zero and length of the square side is now found:

$4\cdot l -\frac{138}{l^{2}} = 0$

$4\cdot l^{3}-138 = 0$

$l^{3} = \frac{138}{4}$

$l = \sqrt[3]{\frac{138}{4} }$

$l \approx 3.3\,ft$

Now, the second derivative offers a criteria to determine if solution leads to an absolute minimum:

$A_{s}'' = 4 + \frac{276}{(3.3\,ft)^{3}}$

$A_{s}'' = 11.7$ (Absolute minimum)

The depth of the tank is:

$x = \frac{34.5\,ft^{3}}{(3.3\,ft)^{2}}$

$x = 3.2\,ft$

6 0

3 years ago

What is the answer?????

irina [24]

A slide with size 20 text font and one or two images.

5 0

3 years ago

List the next four multiples of the unit fraction 1/2 4th grade

OleMash [197]

<h2>The next four multiples of the unit fraction $\dfrac{1}{2}$ are</h2><h2> $\dfrac{2}{2}$ ( 1), $\dfrac{3}{2}$ , $\dfrac{4}{2}$ (2) and $\dfrac{5}{2}$ .</h2>

Step-by-step explanation:

We have:

The unit fraction = $\dfrac{1}{2}$

To find, the next four multiples of the unit fraction $\dfrac{1}{2}$ = ?

∴ The next four multiples of the unit fraction $\dfrac{1}{2}$

The first multiple = $\dfrac{1}{2}\times 2= \dfrac{2}{2} =1$

The second multiple = $\dfrac{1}{2}\times 3= \dfrac{3}{2}$

The third multiple = $\dfrac{1}{2}\times 4= \dfrac{4}{2} =2$

The fourth multiple = $\dfrac{1}{2}\times 5= \dfrac{5}{2}$

∴ The next four multiples of the unit fraction $\dfrac{1}{2}$ are

$\dfrac{2}{2}$ ( 1), $\dfrac{3}{2}$ , $\dfrac{4}{2}$ (2) and $\dfrac{5}{2}$ .

6 0

3 years ago

An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f

Sphinxa [80]

Answer:

Distance between plane and airport is 134.4 miles.

Step-by-step explanation:

Given : An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W.

To find : How far is the plane from the airport.

Solution : Distance from airport to west is 150 miles and then 170 miles in the direction south and angle form is S 49.17° W

Refer the attached picture for clearance.

Applying law of cosines

$c^2=a^2+b^2-2ab Cos(C)$

$c=\sqrt{a^2+b^2-2ab Cos(C)}$

where a= 150 miles

b=170 miles

C= 49.17° angle in degree

c = distance between plane from the airport

Put values in the formula,

$c=\sqrt{a^2+b^2-2ab Cos(C)}$

$c=\sqrt{150^2+170^2-2(150)(170) Cos(49.17^{\circ})}$

$c=\sqrt{22500+28900-51000(0.653)}$

$c=\sqrt{51400-33303}$

$c=\sqrt{18057}$

$c=134.37$

Therefore, Distance between plane and airport is 134.4 miles.

5 0

3 years ago

Read 2 more answers

1. How are pounds per gallon and kilograms per liter alike? How are they different?

Goryan [66]

Answer:

1)= 1 kilogram per liter (kg/l) + 8.35 pound per gallon (lb/gal)

2)= 4.4704 meters per seconds

3)= 12in= 1ft ratio is 12:1

4)= 1ft=12in ratio is 1:12

5)= 3ft= 1 yard ratio is 3:1

6)=1 yard = 3ft ratio 1:3

Step-by-step explanation:

12 in = 1 foot

1 yard = 3 feet

1 yard = 36 in

I hope this helps

7 0

3 years ago