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mr_godi [17]
3 years ago
15

Write a function called changeCharacter that takes three parameters – a character array, its size, and the replacement character

– to change every third character in the array to its replacement character
(C++ coding)
Computers and Technology
1 answer:
ser-zykov [4K]3 years ago
3 0

Method explanation:

  • Defining a method "changeCharacter" that takes three parameters that are "character array", and two integer variable "s, k" in its parameters.
  • Inside the method, a for loop is declared that takes array value and defines a conditional statement that checks the 3rd character value in the array, is used to the array that holds its key-value.
  • Please find the full program in the attachment.

Method description:

void changeCharacter(char* ar, int s, int k)//defining a method changeCharacter that takes three parameters

{

  for(int j = 1; ar[j]!='\0'; j++)//defining a for loop for 3rd character value in array  

  {

      if(j%3== 0)//use if block that check 3rd character value in array  

      {

          ar[j-1] = k; //Changing the 3rd character in array

      }

  }

}

Learn more:

Program: brainly.com/question/12975989

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The value of the mathematical constant e can be expressed as an infinite series: e=1+1/1!+1/2!+1/3!+... Write a program that app
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Answer:

// here is code in c++ to find the approx value of "e".

#include <bits/stdc++.h>

using namespace std;

// function to find factorial of a number

double fact(int n){

double f =1.0;

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if(n==0)

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for(int a=1;a<=n;++a)

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}

// driver function

int main()

{

// variable

int n;

double sum=0;

cout<<"enter n:";

// read the value of n

cin>>n;

// Calculate the sum of the series

  for (int x = 0; x <= n; x++)

  {

     sum += 1.0/fact(x);

  }

  // print the approx value of "e"

    cout<<"Approx Value of e is: "<<sum<<endl;

return 0;

}

Explanation:

Read the value of "n" from user. Declare and initialize variable "sum" to store the sum of series.Create a function to Calculate the factorial of a given number. Calculate the sum of all the term of the series 1+1/1!+1/2!.....+1/n!.This will be the approx value of "e".

Output:

enter n:12

Approx Value of e is: 2.71828

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Answer:

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Explanation:

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