Answer:
The statement in python is as follows:
to_the_power_of(cube_side,3)
Explanation:
As stated as the requirement of the code segment, the statement takes as parameters a variable cube_side and a constant 3.
It then returns the volume of the cube; i.e. cube raise to power 3
<em></em>
<em>See full program below</em>
<em>def to_the_power_of(val,powe):</em>
<em> result = val**powe</em>
<em> print(result)</em>
<em>cube_side = float(input("Cube side: "))</em>
<em>to_the_power_of(cube_side,3)</em>
Answer:
To ensure that the trainees are well acquainted with how to differentiate 568A cables and 568B cables, you must ensure they know appropriate color scheme pattern for the both cables. Also, they are expected to know the correct terminology when using both cables, as 568A is known as a crossover cable and 568B is known as a straight-through cable.
Explanation:
c++, because it is considered as the mother of all programming languages. you can easily access other programming languages if you have a command on c++
The points a b c and d lie on a straight line ab:bd = 1:4 are A line that extends to infinity on both sides and has no curves is called a straight line.AB:BC=3:4.
<h3>What do you call a straight line? </h3>
A line is simply an object in geometry denoted as an object with no width that extends on both sides. A straight line is just a line with no curves.
- AC=AB+BC=3+4=7; AC:CD=2:1, i.e. AC=2; because we get 2 different lengths for AC, we change the given ratio AC:CD to an equivalent one with AC=7 .
- As follows: AC:CD = 2 : 1 = 7 : 3.5 (multiply both sides by 3.5 ) Now we have AC:CD = 7 : 3.5 and AD = AC+CD= 7+3.5 = 10.5,, and the answer is: the ratio BC:AD = 4:10.5.
Read more about the straight line:
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Answer:
Following are the program in the Python Programming language.
#define function
def negative_num(num_list):
#set list type variable
nlist=[]
#set the for loop
for n in num_list:
#check negative numbers
if(n<0):
#add the value of n in list
nlist.append(n)
#return list
return nlist
#set new list type variable that store list
newl=[-5,8,-6,3,-4,9,-7]
#print and call the function
print(negative_num(newl))
<u>Output</u>:
[-5, -6, -4, -7]
Explanation:
Here, we define the function "negative_num" and pass an argument "num_list" in its parameter and inside the function.
- Set new list data type variable "nlist".
- Set the for loop which iterate as the list.
- Set the if conditional statement to check the value of the list is less than 0 then, add that negative values in the variable "nlist".
- Then, return the new list.
Finally, we set a variable "newl" which store the list of negative and positive numbers then, we print and call the function.