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Answer:
5300.
If you're rounding to the nearest hundred you look at the tens place. If its 5 or over you go up. So in this case we'll raise the 2 to a 5 because 6 is above 5.
Answer: There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%.
Step-by-step explanation:
Given: 
The p-value for this hypothesis test is 0.025.
The level of significance is α=0.05
As p-value< α ∵0.025< 0.05
[if p-value< α , we reject
]
then, we reject the null hypothesis.
i.e. We have sufficient evidence to support the alternative hypothesis.
Hence, the correct statement is : There is sufficient evidence to conclude that the proportion of agenda-less meetings is greater than 45%.
Answer: 0.8413
Step-by-step explanation:
Given : Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution.
Mean :
Standard deviation : 
Let x be the random variable that represents the typing speeds for the students.
The z-score :-

For x= 51

Using the standard normal distribution table ,the probability that a randomly selected student has a typing speed of less than 51 words per minute :-

Hence, the probability that a randomly selected student has a typing speed of less than 51 words per minute = 0.8413
Answer: 7
Step-by-step explanation: