k = 5
the equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
To obtain this form use the method of completing the square
Since the coefficient of the x² term is 1 then
add/ subtract (half the coefficient of the x-term )² to x² - 6x
f(x) = x² + 2(- 3)x + 9 - 9 + 14 = (x - 3)² + 5 → k = 5
Answer:For these, n is equal to the term you want. So you substitute the number in for whichever term you want. This means:
a) 1 (1st term) + 5 = 6
2 (2nd term) + 5 = 7
3 (3rd term) + 5 = 8
4 (4th term) + 5 = 9
10 (10th term) + 5 = 15
And so on for b (not going to keep writing the term, I’m sure you get that by now.
b) 2(1) - 1 = (2x1) - 1 = 1
2(2) - 1 = (2x2) - 1 = 3
2(3) - 1 = (2x3) - 1 = 5
2(4) - 1 = (2x4) - 1 = 7
2(10) - 1 = (2x10) - 1 = 19
Hope this helps :)
Answer:
the 4th one
Step-by-step explanation:
Answer: (x-6)/2
Step-by-step explanation:
x=2y+6
x-6=2y
(x-6)/2=y
y=(x-6)/2
