A square of side 4cm is enlarged by a scale factor 2.5. What is the are of the enlarged square

Is it a function or not a function? Please help me??

blagie [28]

Answer:

function

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The ratio between the square of a number and it's cube is 1:3 what is the number

Dimas [21]

Answer:

3

Step-by-step explanation:

Call that number “x”

The square of that number is x^2

Also as the cube is x^3

The ratio between these 2 values is 1:3, this means x^2 / x^3 = 1 / 3

<==> 1 / x = 1 / 3 (eliminate “x^2” for numerator and denominator of the fraction x^2 / x^3 )

<==> x = 1 * 3 / 1 = 3

So, that number is 3 ! This math problem seems simple ;)

4 0

3 years ago

Monisha and Dave each sold more magazine subscriptions as part of a fundraiser Monisha rays have as much money as the rays toget

tatyana61 [14]

Monisha = x/2

Dave = x

x + (x/2) = 213.75

1. Solve for x.

2. Evaluate x/2 to find the total amount raised by Monisha.

Take it from here.

4 0

3 years ago

Evaluate (x + y)^0 for x = -3 and y = 5. 0 -1/2 2 1

marysya [2.9K]

Answer:

The answer is 1.

Step-by-step explanation:

You need to evaluate the expression inside the parentheses.

(-3 + 5)⁰

= (2)⁰

= 1

According to the rule, any number raised to the power of 0 is always equal to 1.

5 0

3 years ago

1.

Eddi Din [679]

Answer:

a) $y=\dfrac{5}{2}x$

b) yes the two lines are perpendicular

c) $y=\dfrac{5}{4}x+6$

Step-by-step explanation:

a) All this is asking if to find a line that is perpendicular to 2x + 5y = 7 AND passes through the origin.

so first we'll find the gradient(or slope) of 2x + 5y = 7, this can be done by simply rearranging this equation to the form $y = mx + c$

$5y = 7 - 2x$

$y = \dfrac{7 - 2x}{5}$

$y = \dfrac{7}{5} - \dfrac{2}{5}x$

$y = -\dfrac{2}{5}x+\dfrac{7}{5}$

this is changed into the $y = mx + c$ , and we easily see that -2/5 is in the place of m, hence $m = \frac{-2}{5}$ is the slope of the line 2x + 5y = 7.

Now, we need to find the slope of its perpendicular. We'll use:

$m_1m_2=-1$ .

here both slopes $m_1$ and $m_2$ are slopes that are perpendicular to each other, so by plugging the value -2/5 we'll find its perpendicular!

$\dfrac{-2}{5}m_2=-1$ .

$m_2=\dfrac{5}{2}$ .

Finally, we can find the equation of the line of the perpendicular using:

$(y-y_1)=m(x-x_1)$

we know that the line passes through origin(0,0) and its slope is 5/2

$(y-0)=\dfrac{5}{2}(x-0)$

$y=\dfrac{5}{2}x$ is the equation of the the line!

b) For this we need to find the slopes of both lines and see whether their product equals -1?

mathematically, we need to see whether $m_1m_2=-1$ ?

the slopes can be easily found through rearranging both equations to $y=mx+c$

Line:1

$2x + 3y =6$

$y =\dfrac{-2x+6}{3}$

$y =\dfrac{-2}{3}x+2$

Line:2

$y = \dfrac{3}{2}x + 4$

this equation is already in the form we need.

the slopes of both equations are

$m_1 = \dfrac{-2}{3}$ and $m_2 = \dfrac{3}{2}$

using

$m_1m_2=-1$

$\dfrac{-2}{3} \times \dfrac{3}{2}=-1$

$-1=-1$

since the product does equal -1, the two lines are indeed perpendicular!

c)if two perpendicular lines have the same intercept, that also means that the two lines meet at that intercept.

we can easily find the slope of the given line, y = − 4 / 5 x + 6 to be $m=\dfrac{-4}{5}$ and the y-intercept is $c=6$ the coordinate at the y-intercept will be (0,6) since this point only lies in the y-axis.