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3 years ago

Determine whether each number is rational or irrational

Mathematics

1 answer:

Temka [501]3 years ago

7 0

Answer:

1. irrational (it's pi. pi goes on forever.)

2. irrational (the ... shows that the number goes on forever.)

3. rational (it is a regular integer)

4. rational (it would be negative 3, an integer.)

5. real, irrational (square root 6 goes on forever, like every non-perfect square root)

6. real, rational, integer, natural, whole (regular counting number)

7. real, rational, integer, natural, whole (regular counting number, 4)

8. real, rational (the .11111... shows the number is a repeating, non terminating number, therefore it is rational and real.)

brainliest is very much appreciated!

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The Blair family was one of the first to come to the original 13 colonies (now part of the USA). They had 4 children. Assuming t

Mumz [18]

Answer:

31.25% probability that the Blair family had at least 3 girls

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it was a girl, or it was not. The probability of a child being a girl is independent of any other children. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

They had 4 children.

This means that $n = 4$

The probability of a child being a girl is 0.5

This means that $p = 0.5$

Probability of at least 3 children:

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{4,3}.(0.5)^{3}.(0.5)^{1} = 0.25$

$P(X = 4) = C_{4,4}.(0.5)^{4}.(0.5)^{0} = 0.0625$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 0.25 + 0.0625 = 0.3125$

31.25% probability that the Blair family had at least 3 girls

3 0

3 years ago

The pie chart to the right shows how adults rate their financial shape. Suppose 4 people are chosen at random from a group of 14

Salsk061 [2.6K]

<u>Question Completion</u>

PIE CHART NUMBERS:

Excellent 9%
Good 41%
Fair 36%
Poor 13%
Other 1%

Answer:

0.000063

Step-by-step explanation:

Number of Respondents, n=1400

Probability that they would rate their financial shape as excellent = 0.09

Number of Those who would rate their financial shape as excellent

=0.09 X 1400

=126

Therefore:

The probability that 4 people chosen at random would rate their financial shape as excellent

$=\dfrac{^{126}C_4 \times ^{1400-126}C_0}{^{1400}C_4} \\=\dfrac{^{126}C_4 \times ^{1274}C_0}{^{1400}C_4}\\=0.000063 $(correct to 6 decimal places)$

6 0

3 years ago

(6 – 4i) (6 + 4i)<br> simplify using imaginary numbers

melamori03 [73]

Answer:

Step-by-step explanation:

7 0

3 years ago

If an object has a Mass of 11g and a volume fo 13mil, what is its density?

tino4ka555 [31]

Step-by-step explanation:

Mass (m) = 11 g

volume (v) = 13 ml

density (d) = ?

We know density is defined as mass per unit volume so

d = m / v

= 11 / 13

= 0.85 g/ml

Density (d) = 0.85 g/ml

5 0

3 years ago

Read 2 more answers

7. Fred had 85 marbles. After a few games, he had 120% of his original number. How many

Gnoma [55]

Answer:

102 marbles

Step-by-step explanation:

100% of 85 is 85.

20% of 85 = 17

85 + 17 = 102

Hope that helps!

4 0

3 years ago