Answer:
H0: μ ≤ 1.30
H1: μ > 1.30
|Test statistic | > 1.833 ; Reject H0
Test statistic = 3.11
Yes
Pvalue = 0.006
Step-by-step explanation:
H0: μ ≤ 1.30
H1: μ > 1.30
Samples, X ; 1.36,1.35,1.33, 1.66, 1.58, 1.32, 1.38, 1.42, 1.90, 1.54
Xbar = 14.84 / 10 = 1.484
Standard deviation, s = 0.187 (calculator)
Decison rule :
|Test statistic | > TCritical ; reject H0
df = n - 1 = 10 - 1 = 9
Tcritical(0.05; 9) = 1.833
|Test statistic | > 1.833 ; Reject H0
Test statistic :
(xbar - μ) ÷ (s/√(n))
(1.484 - 1.30) ÷ (0.187/√(10))
0.184 / 0.0591345
Test statistic = 3.11
Since ;
|Test statistic | > TCritical ; We reject H0 and conclude that water consumption has increased
Pvalue estimate using the Pvalue calculator :
Pvalue = 0.006
