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2 years ago

Find the slope of the line that passes through (2, 8) and (7, 1).

Mathematics

1 answer:

Keith_Richards [23]2 years ago

3 0

Answer:

-7/5

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)

= ( 1-8)/(7-2)

= -7/5

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A number, x , rounded to 1 decimal place is 3.7<br> Write down the error interval for x

Anon25 [30]

The error interval for x is 3.65,3.74.

Given that,

The number rounded to one decimal place is 3.7.

Now based on the above information, the number should be more than or equivalent to 5 at the n+1 place

Like 3.65, 3.66, 3.67, 3.68 till 3.74

Based on the above information, we can conclude that the error interval for x is 3.65,3.74.

Learn more: brainly.com/question/17429689

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2 years ago

Write the slope-intercept form of the equation of the line that passes thrqugh (-4, -3) and is

Zielflug [23.3K]

Answer:

Step-by-step explanation:

Equation of the line y = mx + c

The new line is perpendicular to 2x - 3y = -5

- 3y = - 5 - 2x

3y = 2x + 5

y = $\frac{2x}{3} + \frac{5}{3}$

Since the lines are perpendicular to each other : $m_{1} . m_{2} = -1$

where $m_{1} \ slope \ of \ the \ given \ line \ and \ m_{2} \ slope \ of \ the \ new \line\\$ .

Slope of the given line

$m_{1} = \frac{2}{3}$

Slope of the new line

$\\\frac{2}{3}.m_{2} = -1\\ m_{2} = -1 . \frac{3}{2} = \frac{-3}{2}$

The equation to the new line passing through (-4, -3) and perpendicular to 2x - 3y = -5

$(y - y_{1}) = m_{2}(x-x_{2} )\\\\(y - (-4)) = \frac{-3}{2}(x - (-3)) \\\\(y + 4) = \frac{-3}{2} (x+ 3)\\\\2(y +4) = -3(x+3)\\\\2y + 8 = -3x -9 \\\\2y = -3x - 9 -8\\\\y = \frac{-3x}{2} - \frac{17}{2}$

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3 years ago