Need step by step explanation for this, Thanks

Which statement is true about the marginal frequencies

Tcecarenko [31]

Answer:

D

Step-by-step explanation:

If U add up all the people who played sports and all the 10th graders u will get 191 and 97 and it just said I got it right

3 0

3 years ago

Read 2 more answers

Please help :(( Simplify.

Luden [163]

so the right answer is 16a^20b^24

Look at the attached picture

Hope it will help you..

Good luck on your assignment

~pragya

6 0

3 years ago

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

a

$P(X \ge 1) = 0.509$

b

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$

Here n = 6

So

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{1 * 12376}{38760}]$

$P(X \ge 1) =1- 0.3193$

$P(X \ge 1) = 0.6807$

5 0

3 years ago

Please answer this as quick as you can

vampirchik [111]

Answer:

Step-by-step explanation:

3 and 2 for what i see with the question i don't know if the blue is blocking a tick but i think its 2 and 3 tell me if there a tick on where the blue started so then i might change my answer

8 0

3 years ago

HELP please explain to me how to get this. Which of the following represents a function?

strojnjashka [21]

Answer:

option A : graph is a function

Step-by-step explanation:

(a) option is given is a graph

For graph , the function should pass vertical line test

Draw vertical line for every value of x

The vertical lines cross only one red point at a time

So the graph is a function

(b) When each input has only one output then it is a function

in option B , input 3 has two output -5 and 0

so it is not a function

(c) in option C , input 3 has two output 14 and 19

so it is not a function

(d) in option d , input -1 has two output -11 and 5

so it is not a function

7 0

3 years ago