In this equation, we are solving for f. The first thing we have to do is get rid of the denominator, so we have to multiply both sides by 9, which leaves us with 9C=5*(f-32). Then we divide both sides by 5, which is 9/5C=f-32. The last thing we have to do is add 32 to both sides to isolate f, which gives us our final equation of (5/9)C+32=f.
Answer:
Step-by-step explanation:
area=4×22/7×14²=4×22×28=2464 units²
Answer:
Kindly check explanation
Step-by-step explanation:
Kilogram of flour needed to complete holiday order is atleast 175kg
Number of kilograms available = 34kg
Flour comes in bags each contain 23kg of flour
He wants to buy the smallest number of bags as possible and get the amount of flour he needs.
Let F = number of bags of flours Sergei needs to buy
F = (total number of kilograms needed - number of kilograms available) / kilograms per bag
F = (≥ 175 - 34) / 23
F = ≥ 141 / 23 = ≥ 6.1304347
Since flour is purchased per bag, the smallest number of bags he can possibly buy and still get the amount of flour he need = 7 bags
Answer:
We need to conduct a hypothesis in order to determine if the mean is greater than specified value, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
For this case the significance is 1%. So we need to find a critical value in the normal standard distribution who accumulates 0.99 of the area in the left and 0.01 in the right and for this case this critical value is:
Step-by-step explanation:
Notation
represent the sample mean
represent the standard deviation for the population
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
z would represent the statistic (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to determine if the mean is greater than specified value, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
For this case the significance is 1%. So we need to find a critical value in the normal standard distribution who accumulates 0.99 of the area in the left and 0.01 in the right and for this case this critical value is:
