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Vlad1618 [11]
3 years ago
11

What is the solution to the equation? 3x - 5 =7x -9

Mathematics
2 answers:
maria [59]3 years ago
6 0

Answer:

numbers

=

1

Step-by-step explanation:

1

Add

5

5

5

to both sides of the equation

3

−

5

=

7

−

9

3x-5=7x-9

3x−5=7x−9

3

−

5

+

5

=

7

−

9

+

5

3x-5+{\color{#c92786}{5}}=7x-9+{\color{#c92786}{5}}

3x−5+5=7x−9+5

2

Simplify

Add the numbers

Add the numbers

3

=

7

−

4

3x=7x-4

3x=7x−4

3

Subtract

7

7x

7x

from both sides of the equation

3

=

7

−

4

3x=7x-4

3x=7x−4

3

−

7

=

7

−

4

−

7

3x{\color{#c92786}{-7x}}=7x-4{\color{#c92786}{-7x}}

3x−7x=7x−4−7x

4

Simplify

Combine like terms

Combine like terms

−

4

=

−

4

-4x=-4

−4x=−4

5

Divide both sides of the equation by the same term

−

4

=

−

4

-4x=-4

−4x=−4

−

4

−

4

=

−

4

−

4

\frac{-4x}{{\color{#c92786}{-4}}}=\frac{-4}{{\color{#c92786}{-4}}}

−4−4x=−4−4

6

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

1

Alecsey [184]3 years ago
5 0

Answer:

x=1

Step-by-step explanation:

3x - 5 =7x -9

Subtract 3x from each side

3x - 5-3x =7x-3x -9

-5 = 4x-9

Add 9 to each side

-5+9 = 4x-9+9

4 = 4x

Divide each side by 4

4/4 = 4x/4

1=x

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What is the equation of the line that passes through the points (5, 3) and (-3,-1)?
Liono4ka [1.6K]

Answer:

y=1/2x+1/2

m=1/2

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(5,3) and (-3,-1).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (5,3), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=5 and y1=3.

Also, let's call the second point you gave, (-3,-1), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-3 and y2=-1.

Now, just plug the numbers into the formula for m above, like this:

m=

-1 - 3 over

-3 - 5

or...

m=

-4 over

-8

or...

m=1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(5,3). When x of the line is 5, y of the line must be 3.

(-3,-1). When x of the line is -3, y of the line must be -1.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=1/2x+b. b is what we want, the 1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (5,3) and (-3,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(5,3). y=mx+b or 3=1/2 × 5+b, or solving for b: b=3-(1/2)(5). b=1/2.

(-3,-1). y=mx+b or -1=1/2 × -3+b, or solving for b: b=-1-(1/2)(-3). b=1/2.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(5,3) and (-3,-1)

is

y=1/2x+1/2

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