Erm..
9 I guess..
Good luck?
The experimental probability of rolling a 6 is 9/60 which can be determined by dividing the frequency of the observation 6 with the total frequency of the experiment.
<u>Step-by-step explanation:</u>
Experimental probability is different from theoretical probability because the former is obtained by experimentation while the latter is what we expect theoretically.When we take a number of observations, the experimental probability and theoretical probability need not be the same.
In this question we have to determine the experimental probability of 6. It can be determined by dividing the frequency of the observation 6 by the total frequency of the experiment.
frequency of 6=9
total frequency=frequency of 1+frequency of 2+frequency of 3+frequency of 4+frequency of 5+frequency of 6
=13+11+9+8+10+9
=60
P(6)=frequency of 6/total frequency
=9/60
Answer:
2 yards.
Step-by-step explanation:
If you do what was stated in the problem, you would be left at -2. So, you would need to move up 2 yards to get back to 0.
Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
Answer:
- 3⁷/2⁹
Step-by-step explanation:
- (-2÷3)⁻³ ÷ x = (9÷8)⁻²
- -(2⁻³)×3⁽⁻¹⁾ˣ⁽⁻³⁾ ÷ x = (3²)⁻²×(2⁻³)⁻²
- -2⁻³×3³÷x = 3⁻⁴×2⁶
- x = -2⁻³×3³ ÷ (3⁻⁴×2⁶)
- x = - 2⁻³⁻⁶×3³⁻⁽⁻⁴⁾
- x = -2⁻⁹×3⁷
- x = - 3⁷/2⁹
