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3 years ago

how long should the ladder be if they want to use all the canle they have? use the law of sines to find the length.

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

3 0

Answer: L = 36 feet approximately

The more accurate value is 35.9547644 feet, but this approximate value isn't exact either.

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Explanation:

Ignore the vertical line and any byproducts of it.

Refer to the diagram below. Note that the 95 degree angle is from 15+80 = 95.

We can use the law of sines like so

sin(A)/a = sin(B)/b

sin(75)/200 = sin(10)/L

L*sin(75) = 200*sin(10)

L = 200*sin(10)/sin(75)

L = 35.9547644 which is approximate.

This rounds to roughly 36 feet when rounding to the nearest whole number.

Side note: We never use angle C = 95, and its opposite side.

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Answer:

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Step-by-step explanation:

Use the form below

$\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}$

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Step-by-step explanation:

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Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour

UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

$C(t) = C(0)e^{rt}$

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So $C(0) = 110$

Husband

Half life of 4 hours. So

$C(4) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{4r}$

$e^{4r} = 0.5$

Applying ln to both sides

$\ln{e^{4r}} = \ln{0.5}$

$4r = \ln{0.5}$

$r = \frac{\ln{0.5}}{4}$

$r = -0.1733$

So for the husband

$C(t) = 110e^{-0.1733t}$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.1733t}$

$C(11) = 110e^{-0.1733*11} = 16.35$

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

$C(10) = 0.5C(0) = 0.5*110 = 55$

$C(t) = C(0)e^{rt}$

$55 = 110e^{10}$

$e^{10r} = 0.5$

Applying ln to both sides

$\ln{e^{10r}} = \ln{0.5}$

$10r = \ln{0.5}$

$r = \frac{\ln{0.5}}{10}$

$r = -0.0693$

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

$C(t) = 110e^{-0.0693t}$

$C(11) = 110e^{-0.0693*11} = 51.33$

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

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