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2 years ago

Look at picture pleasee

Mathematics

2 answers:

Sati [7]2 years ago

7 0

Answer:

Point A.

.................

Gwar [14]2 years ago

6 0

Answer:

It is the Picture B.

Step-by-step explanation:

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Jada has read 3/5 of a book. She has read 75 pages so far. How many pages are in the whole book?

saveliy_v [14]

Answer:

125 pages

Step-by-step explanation:

we can use a proportion

3/5=75/x

multiply cross so 75×5 and 3×X

375=3x

÷3. ÷3

x=125

check

75/125=simplified is 3/5

7 0

3 years ago

Which of the following is the reciprocal of x2-2x-8

Lemur [1.5K]

It would be 1 / (x + 2) (x - 4)

4 0

3 years ago

Which best describes the relationship between the line that passes through the points (1, –6) and (3, –2) and the line that pass

Setler [38]

Both lines are parallel, since they have the same slope of 2.

8 0

3 years ago

Monica is a lawyer who earns $8,322.65 every month. She spends $830.98 on rent, $210.36 on food, and $120.45 on gas every month.

Step2247 [10]

She would have $7160.86 left over in cash here's why.....
she starts off with $8,322.65 and spends $830.98 on rent $8,322.65-$830.98= $7,491.67
then spends $210.36 on food and another $120.45 on gas
$7,491.67-$210.36= $7,281.31 - $120.45= $7,160.86 <---- Left over $

7 0

3 years ago

Show that d^2y/dx^2=-2x/y^5, if x^3 + y^3=1

aalyn [17]

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

${3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}$

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

$3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}$

3 0

3 years ago