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3 years ago

Consider the original complex figure and the reduction.

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

8 0

Answer:

1/8

Step-by-step explanation:

I'm going to try to explain this as easy as possible. What I did was take the original shape and divide it by the new shape. For this question, I solved it by dividing 32(the original base) by 4(the new base) and got 8. So the scale factor of the reduction was 1/8.

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Alpha Printing will make 400 brochures for $60. Omega Printing will make 1,000 brochures for $60. How much money will you save o

mixer [17]

Alpha Printing: 400 / 60 =6.6...

Omega Printing: 1,000 / 60 = 16.6...

16.6

- 6.6

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8 0

3 years ago

Read 2 more answers

How many whole servings of 3/2 cups are in 67/3 cups of fruit punch

Lerok [7]

14 8/9 cups of fruit punch

4 0

3 years ago

Click the picture that I sent you

Digiron [165]

Answer: 1211.6585 years

Step-by-step explanation:

The equation for exponential growth is: $P=P_oe^{kt}$

P: final population
P₀: initial population
k: rate of decay (or growth)
t: time

Use the half life information to find k:

$\dfrac{1}{2}P_o=P_oe^{k(800)}\\\\\\\dfrac{1}{2}=e^{800k}\qquad \rightarrow \qquad \text{divided both sides by}\ P_o\\\\\\ln\bigg(\dfrac{1}{2}\bigg)=800k\qquad \rightarrow \qquad \text{applied ln to both sides}\\\\\\\dfrac{ln(\frac{1}{2})}{800}=k\qquad \rightarrow \qquad \text{divided both sides by 800}\\\\\\\large\boxed{-0.000867=k}$

Next, input the information (65% decayed = 35% remaining) and the k-value to find your answer.

$.35P_o=P_oe^{-0.000867t}\\\\\\.35=e^{-0.000867t}\\\\\\ln(.35)=-0.000867t\\\\\\\dfrac{ln(.35)}{-0.000867}=t\\\\\\\large\boxed{1211.6585=t}$

5 0

3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago

Solve:

Basile [38]

$\cfrac{25x^5+10x^2}{5x} = \cfrac{5x(5x^4+2x)}{5x} =5x^4+2x$

3 0

3 years ago