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postnew [5]
2 years ago
9

Help me pls thanks!!!!!!!​

Mathematics
1 answer:
ipn [44]2 years ago
4 0

Answer:

7.   0.37

Decimal value is  - HUNDREDTHS

Fraction value is - \frac{37}{100}

    1.735

Decimal value is  -  TENTHS

Fraction value is - \frac{1735}{1000}

8.   6.075

Decimal value is  - HUNDREDTHS

Fraction value is - \frac{6075}{1000}

      27.05

Decimal value is  - ONES

Fraction value is -  \frac{2705}{100}

9.    0.127

Decimal value is  - THOUSANDTHS

Fraction value is - \frac{127}{1000}

    3.007

Decimal value is  - THOUSANDTHS

Fraction value is - \frac{3007}{1000}

 

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Gavin earned $12.58 and Niko earned $9.35 last week doing chores. They
koban [17]

Answer:

13.07

Step-by-step explanation:

Subtraction dude.

7 0
2 years ago
At a sale this week, a desk is being sold for $561. This is 68% of the original price. What is the original price?​
elixir [45]

Answer:

825

Step-by-step explanation:

hope it helps.good day

5 0
2 years ago
A set of exam scores is normally distributed and has a mean of 80.2 and a standard deviation of 11. What is the probability that
ZanzabumX [31]

Answer:

93.32% probability that a randomly selected score will be greater than 63.7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80.2, \sigma = 11

What is the probability that a randomly selected score will be greater than 63.7.

This is 1 subtracted by the pvalue of Z when X = 63.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{63.7 - 80.2}{11}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

93.32% probability that a randomly selected score will be greater than 63.7.

5 0
3 years ago
i thought this app was suposed to be for homework and i come on here sign up and i see ppl sayin wierd a.s.s sh
rewona [7]
You can this is just the forms basically
3 0
3 years ago
Evaluate C(n, n).<br><br> A. 0<br> B. 1<br> C. n
horrorfan [7]
C(n,n)=\dfrac{n!}{n!(n-n)!}=\dfrac1{0!}=\dfrac11=1

In other words, how many ways are there to choose n objects from a total of n objects? Just one; take all of them at the same time.
4 0
3 years ago
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