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d1i1m1o1n [39]
3 years ago
11

Closest integer to the square root 75

Mathematics
2 answers:
photoshop1234 [79]3 years ago
8 0
Square root of 75<span> is 8.660254

Thus the nearest integer is 9

Hope this helps :)</span>
Anit [1.1K]3 years ago
4 0
I think you want to find the lower and upper bound.

√64 = 8
√81 =9
think it should be 9 it's closer
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Natalie walked 3/5 mile in 1/2 hour. How fast did she walk, in miles per hour?
rjkz [21]

Answer:

Too fast for me.

Step-by-step explanation:

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3 years ago
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Toyland is having a sale. All items are 20% off. How much will you save on an item that usually sells for $95?
aivan3 [116]

Answer:

76$

Step-by-step explanation:

first thing you do is to divide 20/100 to get 0.2  .     After that you multiply 95 by 0.2 to get 19. then subtract the original price to the discount


95-19= 76$

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The equation of a straight line is y+10=5x
MariettaO [177]

Answer:

y=5x-10

Step-by-step explanation:

y+10=5x

y=5x-10

4 0
4 years ago
What is <img src="https://tex.z-dn.net/?f=%205%5E%7B436%7D%20" id="TexFormula1" title=" 5^{436} " alt=" 5^{436} " align="absmidd
Paul [167]

Let's see -

We already know that a number raised to a certain power means repeated multiplication, right? So, all we have to do is multiply 5 × 5 × 5 × 5

436 times! I know, big, right?

This WILL give you a decimal answer and a + sign, so please don't be confused with me!

5 raised to the 436th power is going to give you

= 5.635362925894614e + 304

Crazy, right?

↑   ↑   ↑  Hope this helps! :D

6 0
3 years ago
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A small regional carrier accepted 21 reservations for a particular flight with 19 seats. 10 reservations went to regular custome
Viefleur [7K]

We have 19 available seats, and 21 reservations.

Of the 21 reservations, 10 are sure, so we have 10 out of the 19 seats that are surely occupied.

Then, we have 9 seats for 11 reservations, each one with 44% chance of being occupied.

We have to calculate the probability that the plane is overbooked. This means that more than 9 of the reservations arrive.

This can be modelled as a binomial distirbution with n = 11 and p = 0.44, representing the 44% chance.

Then, we have to calculate P(x > 9).

This can be calculated as:

P(x>9)=P(x=10)+P(x=11)

and each of the terms can be calculated as:

\begin{gathered} P(x=10)=\dbinom{11}{10}\cdot0.44^{10}\cdot0.56^1=11\cdot0.0003\cdot0.56=0.0017 \\ P(x=11)=\dbinom{11}{11}\cdot0.44^{11}\cdot0.56^0=1\cdot0.0001\cdot1=0.0001 \end{gathered}

Then:

P(x>9)=P(x=10)+P(x=11)=0.0017+0.0001=0.0018

We have a probability of 0.18% of being overbooked (P = 0.0018).

If we want to calculate the probability of having empty seats, we need to calculate P(x<9), meaning that less than 9 of the reservations arrive.

We can express this as:

P(x

We have to calculate P(x=9) as we already have calculated the other two terms:

P(x=9)=\dbinom{11}{9}\cdot0.44^9\cdot0.56^2=55\cdot0.0006\cdot0.3136=0.0107

Finally, we can calculate:

\begin{gathered} P(x

There is a probability of 0.9875 that there is one or more empty seats.

Answer:

There is a probability of 0.0018 of being overbooked.

There is a probability of 0.9875 of having at least one empty seat.

7 0
1 year ago
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