To solve this problem we can make the following rule of three
6 ---> 3/4
x ----> 1
Clearing x we have:
x = (1/3/4) * (6)
x = (4/3) * (6)
x = 24/3
x = 8
Answer:
Carlos climbs 8 miles for every mile Lara climbs.
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Lcm= 2
Because
2/2= 1
2/8=4
2/10=5
To determine the correct answer, you will need to find the ranges, means, medians, and mode of City B. You can compare the answers then to answer the question. Please see the attached picture for the necessary information.
The correct choice is the first statement about the mode for City B.
Answer:
Function 1 written in vertex form is f(x) = -x^2 + 8x - 15 = -(x^2 - 8x + 15) = -(x^2 - 8x + 16 + 15 - 16) = -(x - 4)^2 - (-1) = -(x - 4)^2 + 1
Therefore, vertex = (4, 1)
Function 2 written in vertex form is f(x) = -x^2 + 4x + 1 = -(x^2 - 4x - 1) = -(x^2 - 4x + 4 - 1 - 4) = -(x - 2)^2 - (-5) = -(x - 2)^2 + 5
Therefore vertex = (2, 5)
Function 1 has a maximum at y = 1 and function 2 has a maximum at y = 5. Therefore, function 2 has a larger maximum.
Step-by-step explanation: